-6x^2-8x+8=10

Solution for -6x^2-8x+8=10 equation:

-6x^2-8x+8=10

We move all terms to the left:

-6x^2-8x+8-(10)=0

We add all the numbers together, and all the variables

-6x^2-8x-2=0

a = -6; b = -8; c = -2;
Δ = b2-4ac
Δ = -82-4·(-6)·(-2)
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-4}{2*-6}=\frac{4}{-12}
=-1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+4}{2*-6}=\frac{12}{-12}
=-1
$